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Tushar
Asked 2d 6h ago

In figure below, $Δ\ ACB\ ∼\ Δ\ APQ$. If $BC\ =\ 8\ cm$, $PQ\ =\ 4\ cm$, $BA\ =\ 6.5\ cm$ and $AP\ =\ 2.8\ cm$, find $CA$ and $AQ$.



Answered   6 Views
Solutions :
Akhilesh
Answered 2d 6h ago

Given:


In the given figure $Δ\ ACB\ ∠¼\ Δ\ APQ$.

$BC\ =\ 8\ cm$, $PQ\ =\ 4\ cm$, $BA\ =\ 6.5\ cm$ and $AP\ =\ 2.8\ cm$.


To do:


We have to find the value of $CA$ and $AQ$.

Solution:


$Δ\ ACB\ ∠¼\ Δ\ APQ$  (given)


Therefore,

$\frac{BA}{AQ} = \frac{CA}{AP} = \frac{BC}{PQ}$   (Corresponding parts of similar triangles are proportional)


$\frac{6.5}{AQ} = \frac{8}{4}$

$AQ = \frac{6.5 \times 4}{8}$

$AQ = 3.25\ cm$

And,

$\frac{CA}{AP} = \frac{BC}{PQ}$

$\frac{CA}{2.8} = \frac{8}{4}$

$CA = 2.8 \times 2$

$CA = 5.6\ cm$

Hence, the values of $CA$ and $AQ$ are $5.6\ cm$ and $3.25\ cm$ respectively.

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